JSYML
2007
15 years 2 months ago
2007
We show that every nonzero Σ0 2 enumeration degree bounds a nonsplitting nonzero enumeration degree.
106
click to vote
AML
2010
15 years 3 months ago
2010
Abstract We prove that a sequence of sets containing representatives of cupping partners for every nonzero 0 2 enumeration degree cannot have a 0 2 enumeration. We also prove that ...