JSYML
2007
14 years 8 months ago
2007
We show that every nonzero Σ0 2 enumeration degree bounds a nonsplitting nonzero enumeration degree.
58
Voted
AML
2010
14 years 9 months ago
2010
Abstract We prove that a sequence of sets containing representatives of cupping partners for every nonzero 0 2 enumeration degree cannot have a 0 2 enumeration. We also prove that ...